a. √3.√6
b. √3 (2√6 + 2√/24)
secepatnya jangan asal plis![]()
b. √3 (2√6 + 2√/24)
secepatnya jangan asal plis
Penjelasan dengan langkah-langkah:
[tex] \sqrt{3} \times \sqrt{6} \\ \sqrt{18} \\ 3 \sqrt{2} [/tex]
[tex] \sqrt{3} (2 \sqrt{6} + 2 \sqrt{24} ) \\ \sqrt{3} (2 \sqrt{6} + 4 \sqrt{6} ) \\ \sqrt{3} \times 6 \sqrt{6} \\ 6 \sqrt{18} \\ 18 \sqrt{2} [/tex]
SOAL A.
[tex]( \sqrt{3})( \sqrt{6}) = \sqrt{(3 \times 6)} = \sqrt{18} = \sqrt{9 \times 2} = 3 \sqrt{2} [/tex]
SOAL B.
[tex]( \sqrt{3})(2 \sqrt{6} + 2 \sqrt{24})[/tex]
[tex] = ( \sqrt{3})(2 \sqrt{6} + 2 \sqrt{4 \times 6})[/tex]
[tex] = ( \sqrt{3})(2 \sqrt{6} + 2 \times 2 \sqrt{6})[/tex]
[tex]= ( \sqrt{3})(2 \sqrt{6} + 4 \sqrt{6})[/tex]
[tex] = ( \sqrt{3})(6 \sqrt{6})[/tex]
[tex] = 6 \sqrt{18} = 6 \sqrt{9 \times 2} = 6 \times 3 \sqrt{2} = 18 \sqrt{2} [/tex]
[answer.2.content]
